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Mathematics

Euler's Formula

The equation that unifies trigonometry, complex numbers, and exponentials.

9 min read·June 1, 2026

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The most beautiful equation#

Richard Feynman called it "the most remarkable formula in mathematics." Mathematicians regularly vote it the most beautiful equation of all time. When θ=π\theta = \pi, Euler's formula gives:

eiπ+1=0e^{i\pi} + 1 = 0

Five fundamental constants — ee, ii, π\pi, 11, 00 — in a single equation. But this is the punch line. To understand why it's true, and why it matters, we need to understand what eiθe^{i\theta} actually means.

What does it mean to exponentiate by a complex number?#

For real numbers, exe^x is the unique function equal to its own derivative, with e0=1e^0 = 1. But what does eiθe^{i\theta} mean when the exponent is imaginary?

The answer lies in the Taylor series. We know:

ex=1+x+x22!+x33!+x44!+e^x = 1 + x + \frac{x^2}{2!} + \frac{x^3}{3!} + \frac{x^4}{4!} + \cdots

Substitute x=iθx = i\theta and use i2=1i^2 = -1, i3=ii^3 = -i, i4=1i^4 = 1:

eiθ=1+iθθ22!iθ33!+θ44!+e^{i\theta} = 1 + i\theta - \frac{\theta^2}{2!} - \frac{i\theta^3}{3!} + \frac{\theta^4}{4!} + \cdots

Separating real and imaginary parts:

eiθ=(1θ22!+θ44!)cosθ+i(θθ33!+θ55!)sinθe^{i\theta} = \underbrace{\left(1 - \frac{\theta^2}{2!} + \frac{\theta^4}{4!} - \cdots\right)}_{\cos\theta} + i\underbrace{\left(\theta - \frac{\theta^3}{3!} + \frac{\theta^5}{5!} - \cdots\right)}_{\sin\theta}

Therefore: eiθ=cosθ+isinθe^{i\theta} = \cos\theta + i\sin\theta.

The geometry: a point on the unit circle#

In the complex plane, a complex number a+bia + bi is a point with real part aa and imaginary part bb. The number eiθ=cosθ+isinθe^{i\theta} = \cos\theta + i\sin\theta has:

  • Real part: cosθ\cos\theta
  • Imaginary part: sinθ\sin\theta

Its distance from the origin: cos2θ+sin2θ=1\sqrt{\cos^2\theta + \sin^2\theta} = 1. It always lies on the unit circle. As θ\theta increases, the point rotates counterclockwise. Euler's formula says: eiθe^{i\theta} is a rotation by angle θ\theta.

Watch the gold phasor rotate around the unit circle. The blue horizontal projection is cosθ\cos\theta, the violet vertical projection is sinθ\sin\theta. The traces on the right show exactly how these projections form the familiar sine and cosine waves — not as abstract functions, but as shadows of circular motion.

Why multiplication equals rotation#

One of the most powerful consequences: multiplying two complex numbers adds their angles. If z1=eiαz_1 = e^{i\alpha} and z2=eiβz_2 = e^{i\beta}, then:

z1z2=eiαeiβ=ei(α+β)z_1 \cdot z_2 = e^{i\alpha} \cdot e^{i\beta} = e^{i(\alpha + \beta)}

Multiplication in the complex plane is rotation. This makes complex numbers the natural language of anything that rotates or oscillates.

Frequency is circular#

Euler's formula is why signals engineers write everything as complex exponentials. A sinusoidal signal at frequency ff:

Acos(2πft+ϕ)=Re[Aei(2πft+ϕ)]A\cos(2\pi f t + \phi) = \text{Re}\left[A e^{i(2\pi f t + \phi)}\right]

The complex exponential e2πifte^{2\pi i f t} rotates around the unit circle at ff revolutions per second. The Fourier transform decomposes any signal by asking: "how much of this rotating-arrow frequency is present?" The inner product that the Fourier transform computes is measuring correlation with each possible rotation rate.

This is the picture to keep in your head: a sine wave is just the shadow of a spinning arrow. Crank the frequency up and the arrow spins faster, so its shadow oscillates faster — the wave compresses. Every "frequency" in signal processing is literally a rotation rate, and that single idea is why complex exponentials, not sines and cosines, are the natural language of waves.

De Moivre's theorem and angle identities#

With Euler's formula, the double-angle identities become trivial:

(cosθ+isinθ)2=e2iθ=cos(2θ)+isin(2θ)(\cos\theta + i\sin\theta)^2 = e^{2i\theta} = \cos(2\theta) + i\sin(2\theta)

Expanding the left side: cos2θsin2θ+2isinθcosθ\cos^2\theta - \sin^2\theta + 2i\sin\theta\cos\theta. Matching real and imaginary parts:

cos(2θ)=cos2θsin2θsin(2θ)=2sinθcosθ\cos(2\theta) = \cos^2\theta - \sin^2\theta \qquad \sin(2\theta) = 2\sin\theta\cos\theta

Results that once required geometric proof fall out as algebra. De Moivre's theorem ((cosθ+isinθ)n=cos(nθ)+isin(nθ)(\cos\theta + i\sin\theta)^n = \cos(n\theta) + i\sin(n\theta)) and all the angle addition formulas follow immediately.

A window into quantum mechanics#

In quantum mechanics, the state of a particle is described by a wave function ψ(x,t)\psi(x, t). For a free particle with definite momentum pp:

ψ(x,t)=ei(kxωt)\psi(x, t) = e^{i(kx - \omega t)}

where k=p/k = p/\hbar is the wave number and ω=E/\omega = E/\hbar is the angular frequency. This is a complex exponential — a rotating phasor — propagating through space and time. Everything about quantum mechanical interference, the double-slit experiment, and particle statistics descends from how these phasors add and cancel.

Euler's formula isn't just a beautiful identity. It's the mathematics of rotation, periodicity, and wave behavior. It appears wherever things repeat.

Key takeaways
  • eiθ=cosθ+isinθe^{i\theta} = \cos\theta + i\sin\theta falls straight out of the Taylor series for exe^x with x=iθx = i\theta.
  • Geometrically, eiθe^{i\theta} is a point on the unit circle, so eiθe^{i\theta} is a rotation by θ\theta — and a sine wave is the shadow of that spinning arrow.
  • Multiplying complex numbers adds their angles, which makes complex exponentials the natural language of anything that rotates or oscillates.
  • "Frequency" is a rotation rate: e2πifte^{2\pi i f t} spins ff times per second — the foundation of the Fourier transform.
  • The same rotating phasor describes quantum wave functions, so interference and the double slit are Euler's formula in disguise.
Check your understanding
1. What does Euler's formula geometrically represent in the complex plane when theta increases?
2. How does Euler's formula simplify the derivation of double-angle trigonometric identities?
3. Why do quantum mechanical wave functions for free particles take the form e raised to the i(kx - omega t)?
0 / 3 answered

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